The expected values are: E(X) = (0.3 × 2) + (0.4 × 6) + (0.3 × 10) = 6 and E(Y) = (0.3 × 10.0) + (0.4 × 2.5) + (0.3 × 0.0) = 4. The covariance is COV(XY) = ((0.3 × ((2 − 6) × (10 − 4))) + ((0.4 × ((6 − 6) × (2.5 − 4))) + (0.3 × ((10 − 6) × (0 − 4))) = −12.
